College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 3 - Section 3.1 - Functions - 3.1 Assess Your Understanding - Page 213: 112

Answer

$\mathrm{a}$. $P(x)=-0.1x^{2}+23x-400$ $\mathrm{b}$. $P(30)={{\$}} 200$ $\mathrm{c}$. The profit on the sale of 30 clocks is ${{\$}} 200.$

Work Step by Step

$a$. $P(x)=R(x)-C(x)$ $=30x-(0.1x^{2}+7x+400)$ $=30x-0.1x^{2}-7x-400$ $=-0.1x^{2}+23x-400$ $b$. Substitute $x=30$ into the result of a. $P(30)=-0.1(30)^{2}+23(30)-400$ $=-90+690-400$ $={{\$}} 200$ $c$. When 30 clocks are sold, the profit is ${{\$}} 200.$
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