Answer
$x=4\pm2\sqrt3$
Work Step by Step
$x^2-8x+4=(x-4)^2-16+4=(x-4)^2-12=0\\(x-4)^2=12\\(x-4)=\pm2\sqrt3\\x=4\pm2\sqrt3$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 2 - Section 2.2 - Graphs of Equations in Two Variables; Intercepts; Symmetry - 2.2 Assess Your Understanding - Page 167: 95
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