## College Algebra (10th Edition)

If we plug in the respective $x$ and $y$ values of $(x,y)$, we can check if it satisfies the equation, if it does, it is on the graph, if it doesn't it is not on the graph. Hence here: $(1,2)\rightarrow1+1=2\ne2^3=8$, so it is not on the graph $(0,1)\rightarrow0+1=1=1^3$, so it is on the graph $(-1,0)\rightarrow-1+1=0\ne0^3$, so it is on the graph