## College Algebra (10th Edition)

$x=3,=-3$
To solve the equation: $x^2-9=0$ We first add 9 to both sides: $x^2-9+9=0+9$ $x^2=9$ To solve for x, we now take the square root of both sides: $\sqrt{ x^2}=\sqrt 9$ So, $x=3,=-3$