College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Review Exercises - Page 196: 31

Answer

The center of the circle is (1,-2), and its radius is about 5.66 units. The equation is $(x-1)^2+(y+2)^2=32$

Work Step by Step

In order to find the center using these points, we find the midpoint between them: $h=\dfrac{5+(-3)}{2},k=\dfrac{-6+2}{2}$ $h=\dfrac{2}{2},k=\dfrac{-4}{2}$ $h=1, k=-2$ Now, we can use the center and one of the points to find the distance between them, which is the radius: $r=\sqrt{(1-5)^2+(-2-(-6))^2}$ $r=\sqrt{(-4)^2+(4)^2}$ $r=\sqrt{16+16}$ $r=\sqrt{32}\approx5.66$ units The equation would then be: $(x-1)^2+(y-(-2))^2=(\sqrt{32})^2$ $(x-1)^2+(y+2)^2=32$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.