College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Review Exercises - Page 195: 10

Answer

The x-intercepts are (-1,0) and (0,0) The y-intercepts are (0,-2) and (0,0) The equation has no symmetry with respect to the x-axis, y-axis, or origin.

Work Step by Step

To find the x-intercept(s), we set y to 0 and solve for x: $x^2+x+0^2+2(0)=0$ $x^2+x=0$ $x(x+1)=0$ $x_1=0$ $x_2+1=0\rightarrow x_2=-1$ To find the y-intercept(s), we set x to y and solve for y: $0^2+0+y^2+2y=0$ $y^2+2y=0$ $y(y+2)=0$ $y_1=0$ $y_2+2=0\rightarrow y_2=-2$ To test for symmetry with respect to the x-axis, we substitute y for -y and check if it equals the original equation: $x^2+x+(-y)^2+2(-y)=0$ $x^2+x+y^2-2y=0$ nope To test for symmetry with respect to the y-axis, we substitute x for -x and check if it equals the original equation: $(-x)^2+(-x)+y^2+2y=0$ $x^2-x+y^2+2y=0$ nope To test for symmetry with respect to the origin, we substitute x for -x, substitute y for -y and check if it equals the original equation: $(-x)^2+(-x)+(-y)^2+2(-y)=0$ $x^2-x+y^2-2y=0$ nope
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