College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 10 - Test - Page 709: 10

Answer

See below.

Work Step by Step

If we want to choose $k$ elements out of $n$ regarding the order, not allowing repetition, we can do this in $_{n}P_k=\frac{n!}{(n-k)!}$ ways. The order matters here when choosing the two horses, thus we have to use permutations. We have $8$ horses for $2$ spots, thus $_{8}P_{2}=\frac{8!}{(8-2)!2!}=56$
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