Answer
$90, 720$
Work Step by Step
The number of permutation of $n$ objects that are not all distinct is:
$\frac{n!}{n_{1}! \times n_{2}! ... n_{k}!}$
where $n_{1} + n_{2} + ... + n_{k} = n$ and $n_{1}$ are of one kind, $n_{2}$ are of a second kind, ... and $n_{k}$ are of a $k$th kind.
$\frac{9!}{2! \times 2! \times 1! \times 1! \times 1! \times 1! \times 1!} = \frac{362,880}{2 \times 2} = 90,720$
