## College Algebra (10th Edition)

Published by Pearson

# Chapter 10 - Section 10.1 - Counting - 10.1 Assess Your Understanding - Page 688: 39

#### Answer

$\frac{1}{18}=x$

#### Work Step by Step

$\log_a x+\log_a y=\log_a (x\cdot y)$, hence $\log_3x+\log_32=\log_3{(2x)}$. We know that if $a^x=y$, then $\log_a y=x$ and vice versa. Hence here $3^{-2}=2x\\\frac{1}{9}=2x\\\frac{1}{18}=x$

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