College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 10 - Section 10.1 - Counting - 10.1 Assess Your Understanding - Page 687: 29

Answer

Number of investors having only IBM shares is $15$.

Work Step by Step

There are three stocks IBM, AT&T and GE. This can be presented in a Venn Diagram where I represent IBM, A represents, AT&T and G represents GE. There are 5 investors having shares in all the companies, 20 investors had shares in IBM and AT&T. 15 investors have shares in GE and AT&T, and 20 investors have shares in GE and IBM. In total, 45 investors had GE shares, 40 investors had AT&T shares, and 50 investors had IBM shares. I = 50 G = 45 A = 40 A∩G = 15 G∩I = 20 A∩I = 20 A∩G∩I = 5 Then, A∩G only = A∩G - A∩G∩I = 15 – 5 = 10 G∩I only = G∩I - A∩G∩I = 20 – 5 = 15 A∩I only = A∩I - A∩G∩I = 20 – 5 = 15 Then, Number of investors having only GE shares, G only = G - G∩I only - A∩G only - A∩G∩I = 45 – 15 – 10 – 5 = 15 Number of investors having only AT&T shares, A only = A - A∩I only - A∩G only - A∩G∩I = 40 – 15 – 10 – 5 = 10 Number of investors having only IBM shares, I only = I - G∩I only - A∩I only - A∩G∩I = 50 – 15 – 15 – 5 = 15
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