College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.7 - Problem Solving: Interest, Mixture, Uniform Motion, Constant Rate Job Applications - 1.7 Asses Your Understanding - Page 143: 48

Answer

$1350miles$ Note: this is total distance traveled. Thus, the plane could go to a given destination and back as long as the distance between the two locations was less than or equal to 675 miles.

Work Step by Step

The speed of the plane because of the wind will be $300-30=270miles/h$ hence the covered distance: $5h\cdot270miles/h=1350miles$
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