College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.7 - Problem Solving: Interest, Mixture, Uniform Motion, Constant Rate Job Applications - 1.7 Asses Your Understanding - Page 142: 45


$40$ grams.

Work Step by Step

Let $y$ be the amount of $12$ karat gold, then $60-y$ is the amount of pure gold. Then our equation is: $y\cdot\frac{12}{24}+(60-y)\frac{24}{24}=60\cdot\frac{16}{24}\\0.5y+60-y=40\\20=0.5y\\40=y$
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