College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.5 - Solving Inequalities - 1.5 Assess Your Understanding - Page 129: 126

Answer

See below.

Work Step by Step

$x^2+1\lt-5\\x^2\lt-6$ But $x^2$ is non-negative, thus the inequality has no solution. $x^2+1\leq1\\x^2\leq0$ But $x^2$ is non-negative, thus the inequality has one solution only: $x=0$.
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