College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.2 - Quadratic Equations - 1.2 Assess Your Understanding - Page 103: 113

Answer

The student worked around 29 hours each week.

Work Step by Step

Since g is given the equation will result as: $2.97=-0.0006h^2+0.015h+3.04$ Subtracting both sides by 2.97 will result as: $0=-0.0006h^2+0.015+0.07$ Using the quadratic formula, the number of hours (h) can be found: $h=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ a=-0.0006, b=0.015, and c=0.07, so: $h=\frac{-0.015\pm\sqrt{0.015^2-4(-0.0006)(0.07)}}{2(-0.0006)}$ $h=\frac{-0.015\pm\sqrt{0.000225+0.000168}}{-0.0012}$ $h=\frac{-0.015\pm\sqrt{0.000393}}{-0.0012}$ $h\approx\frac{-0.015\pm0.019824}{-0.0012}$ Since the positive option will result in a negative answer, the negative option will be used: $h\approx\frac{-0.015-0.019824}{-0.0012}$ $h\approx\frac{-0.034824}{-0.0012}$ $h\approx29$
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