College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Appendix - Graphing Utilities - 5 Square Screens - 5 Exercises - Page A8: 9


See below.

Work Step by Step

For a square screen $\frac{X_{max}-X_{min}}{Y_{max}-Y_{min}}=1.6.$ Hence here $Y_{max}-Y_{min}=16/1.6=10$. Also we need $(4,8)$ to be contained, thus $Y_{min}\lt 8\lt Y_{max}$. Thus a possible solution is $Y_{min} = 0, Y_{max} = 10, and \ Y_{scl} = 1$.
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