Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Monitoring Progress - Page 484: 24

Answer

$-14\sqrt{7}$.

Work Step by Step

The given expression is $=4\sqrt{7}-6\sqrt{63}$ Factor as square terms. $=4\sqrt{7}-6\sqrt{9\cdot 7}$ Use $9=3^2$. $=4\sqrt{7}-6\sqrt{3^2\cdot 7}$ Use product property of square roots. $=4\sqrt{7}-6\sqrt{3^2}\cdot \sqrt{7}$ Simplify. $=4\sqrt{7}-6\cdot 3 \sqrt{7}$ $=4\sqrt{7}-18 \sqrt{7}$ Use distributive property. $=(4-18)\sqrt{7}$ Subtract. $=-14\sqrt{7}$.
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