Answer
Vertex: $(3,6)$.
Axis of symmetry: $x=3$
Work Step by Step
The quadratic function in the form $y=a(x-h)^2+k$ has the vertex $(h,k)$ and the axis of symmetry $x=h$.
Given: $$f(x)=3(x-3)^2+6$$ Therefore $h=3$, $k=6$.
The vertex is: $$(h,k)=(3,6).$$ The axis of symmetry is: $$x=3.$$