Answer
$-(y-2)(2y-3)$.
Work Step by Step
The given polynomial is
$=-2y^2+7y-6$
Factor out $-1$.
$=-(2y^2-7y+6)$
Rewrite $-7y$ as $-4y-3y$.
$=-(2y^2-4y-3y+6)$
Group the terms.
$=-[(2y^2-4y)+(-3y+6)]$
Factor each group.
$=-[2y(y-2)-3(y-2)$
Factor out $(y-2)$.
$=-(y-2)(2y-3)$
Hence, the factor of the polynomial is $-(y-2)(2y-3)$.
