Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 7 - Polynomial Equations and Factoring - Chapter Review - Page 411: 23

Answer

$(z+3)(z-7)$.

Work Step by Step

The given polynomial is $=z^2-4z-21$ Rewrite $-4z$ as $3z-7z$. $=z^2+3z-7z-21$ Group the terms. $=(z^2+3z)+(-7z-21)$ Factor each group. $=z(z+3)-7(z+3)$ Factor out $(z+3)$. $=(z+3)(z-7)$ Hence, the factor of the polynomial is $(z+3)(z-7)$.
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