Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 7 - Polynomial Equations and Factoring - 7.6 - Factoring ax^2 + bx + c = 0 - Exercises - Page 395: 16

Answer

$3(3v+2)(2v-3)$.

Work Step by Step

The given polynomial is $=18v^2-15v-18$ Factor out $3$. $=3(6v^2-5v-6)$ Rewrite $-5v$ as $4v-9v$. $=3(6v^2+4v-9v-6)$ Group the terms. $=3[(6v^2+4v)+(-9v-6)]$ Factor each group. $=3[2v(3v+2)-3(3v+2)]$ Factor out $(3v+2)$. $=3(3v+2)(2v-3)$ Hence, the factor of the polynomial is $3(3v+2)(2v-3)$.
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