Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 7 - Polynomial Equations and Factoring - 7.1-7.4 - Quiz - Page 384: 11

Answer

$y^3+11y^2+15y-27$.

Work Step by Step

The given expression is $=(y+9)(y^2+2y-3)$ Distribute $(y^2+2y-3)$ to each term of $(y+9)$. $=y(y^2+2y-3)+9(y^2+2y-3)$ Use distributive property. $=y(y^2)+y(2y)+y(-3)+9(y^2)+9(2y)+9(-3)$ Multiply. $=y^3+2y^2-3y+9y^2+18y-27$ Combine like terms. $=y^3+11y^2+15y-27$ Hence, the product is $y^3+11y^2+15y-27$.
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