Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 2 - Solving Linear Inequalities - 2.6 - Solving Absolute Value Inequalities - Exercises - Page 91: 16

Answer

$2\lt u$ or $-1\gt u$ The graph is shown below.

Work Step by Step

The given inequality is $\Rightarrow -3|2-4u|+5\lt-13$ Subtract $5$ from each side. $\Rightarrow -3|2-4u|+5-5\lt-13-5$ Simplify. $\Rightarrow -3|2-4u|\lt-18$ Divide each side by $-3$. Reverse the inequality symbol. $\Rightarrow \frac{-3|2-4u|}{-3}\gt\frac{-18}{-3}$ Simplify. $\Rightarrow |2-4u|\gt6$ Write a compound inequality. $\Rightarrow 2-4u\lt -6$ or $2-4u\gt 6$ Add $4u+6$ to each side of the first inequality and $4u-6$ to each side of the second inequality. $\Rightarrow 2-4u+4u+6\lt -6+4u+6$ or $2-4u+4u-6\gt 6+4u-6$ Simplify. $\Rightarrow 8\lt 4u$ or $-4\gt 4u$ Divide each side by $4$. $\Rightarrow \frac{8}{4}\lt \frac{4u}{4}$ or $\frac{-4}{4}\gt \frac{4u}{4}$ Simplify. $\Rightarrow 2\lt u$ or $-1\gt u$ Hence, the solution is $2\lt u$ or $-1\gt u$.
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