Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 10 - Radical Functions and Equations - 10.3 - Solving Radical Equations - Exercises - Page 565: 40

Answer

The solution is $r=8$.

Work Step by Step

The given equation is $\Rightarrow \sqrt[3]{r+19}=3$ Cube each side of the equation. $\Rightarrow (\sqrt[3]{r+19})^3=3^3$ Simplify. $\Rightarrow r+19=27$ Subtract $19$ from each side. $\Rightarrow r+19-19=27-19$ Simplify. $\Rightarrow r=8$ Check $r=8$. $\Rightarrow \sqrt[3]{r+19}=3$ $\Rightarrow \sqrt[3]{8+19}=3$ $\Rightarrow \sqrt[3]{27}=3$ $\Rightarrow \sqrt[3]{3^3}=3$ $\Rightarrow 3=3$ True. Hence, the solution is $r=8$.
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