Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 10 - Radical Functions and Equations - 10.2 - Graphing Cube Root Functions - Exercises - Page 556: 43

Answer

The factor of the given polynomial is $3(x+6)(x-2)$.

Work Step by Step

The given polynomial is $=3x^2+12x-36$ Factor out $3$. $=3(x^2+4x-12)$ Rewrite $4x$ as $6x-2x$. $=3(x^2+6x-2x-12)$ Group the terms. $=3[(x^2+6x)+(-2x-12)]$ Factor each group. $=3[x(x+6)-2(x+6)]$ Factor out $(x+6)$. $=3(x+6)(x-2)$ Hence, the factor of the given polynomial is $3(x+6)(x-2)$.
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