Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - 1.5 - Rewriting Equations and Formulas - Monitoring Progress - Page 37: 8

Answer

$l=\frac{S-\pi r^2}{\pi r}$ where $r\neq 0$.

Work Step by Step

The given formula is $\Rightarrow S=\pi r^2+\pi rl$ Subtract $\pi r^2$ from each side. $\Rightarrow S-\pi r^2=\pi r^2+\pi rl-\pi r^2$ Simplify. $\Rightarrow S-\pi r^2=\pi rl$ Divide each side by $\pi r$. $\Rightarrow \frac{S-\pi r^2}{\pi r}=\frac{\pi rl}{\pi r}$ Simplify. $\Rightarrow \frac{S-\pi r^2}{\pi r}=l$ Hence, the solution for the indicated variable is $l=\frac{S-\pi r^2}{\pi r}$ where $r\neq 0$.
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