Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - 1.5 - Rewriting Equations and Formulas - Exploration - Page 35: 1

Answer

See the explanation

Work Step by Step

$\textbf{Part (a)}$ The area formula for a parallelogram is: $$A=bh\tag{1},$$ where: • $A$ is the area, • $b$ is the base, • $h$ is the height. $\textbf{Part (b)}$ The problem gives: • $A = 30\text{ inch}^2$ • $h= 5\text{ inch}$ Substitute these values into equation $(1)$: $$30=b\cdot 5.$$ Solve for $b$. $1.$ Divide both sides by $5$: $$\frac{30}{5}=\frac{b\cdot 5}{5}.$$ $2.$ Simplify $$6=b.$$ So, the base is $b=6\text{ inch}$. $\textbf{Part (c)}$ Start with formula $(1)$. Solve for $b$: $1.$ Divide both sides by $h$: $$\frac{A}{h}=b.$$ $2.$ Rearrange the formula: $$b=\frac{A}{h}.$$ Now substitute the given values ($A$, $h$): $$b=\frac{30}{5}.$$ Simplify: $$b=6.$$ $\textbf{Part (d)}$ Similarities: • Both methods use the formula $(1)$ and algebraic steps to solve for $b$. • Both yield the same result: $6\text{ inch}$. Differences: • In part (b), substitution of values ($A$ and $h$) was done first, followed by solving for $b$. • In part (c), the formula was rearranged to solve for $b$ first and then values were substituted.
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