#### Answer

The width of the court is $36\; feet$.
The length of the court is $78\;feet$.

#### Work Step by Step

The given perimeter of the tennis court is $228\;feet$.
Length of the court is $2w+6$.
Width of the court is $w$.
Perimeter of the court is $P=2($length $+$ width$)$
Substitute all the values.
$\Rightarrow 228=2(2w+6+w)$
Add like terms.
$\Rightarrow 228=2(3w+6)$
Use distributive property.
$\Rightarrow 228=6w+12$
Subtract $12$ from each side.
$\Rightarrow 228-12=6w+12-12$
Simplify.
$\Rightarrow 216=6w$
Divide each side by $6$.
$\Rightarrow 36=w$
Length of the court is
$2w+6=2(36)+6=72+6=78$
Hence, the width of the court is $36\; feet$ and the length of the court is $78\;feet$.