Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Prerequisites - Review Exercises - Page 64: 95

Answer

$\frac{x-8}{15}$

Work Step by Step

$\frac{x^2-64}{5(3x+24)}=\frac{x^2-8^2}{5[3x+3(8)]}=\frac{(x+8)(x-8)}{5(3)(x+8)}=\frac{x-8}{15}$
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