Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Prerequisites - Review Exercises - Page 63: 55


$\frac{3}{\sqrt 7-1}$

Work Step by Step

$\frac{\sqrt 7+1}{2}=\frac{\sqrt 7+1}{2}\frac{\sqrt 7-1}{\sqrt 7-1}=\frac{\sqrt 7(\sqrt 7)+\sqrt 7(-1)+1(\sqrt 7)+1(-1)}{2(\sqrt 7-1)}=\frac{(\sqrt 7)^2-1}{2(\sqrt 7-1)}=\frac{7-1}{2(\sqrt 7-1)}=\frac{6}{2(\sqrt 7-1)}=\frac{2(3)}{2(\sqrt 7-1)}=\frac{3}{\sqrt 7-1}$
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