Answer
$30\sqrt {41}$
Work Step by Step
Distance (d) = $\sqrt {(x_1-x_2)^2+(y_1-y_2)^2}$
Hence, $\sqrt {(120-0)^2+(150-0)^2}$=$\sqrt {14400+22500}$=$30\sqrt {41}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.6 - The Rectangular Coordinate System and Graphs - Exercises - Page 58: 37
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