Answer
$kx(Q-x)$
Work Step by Step
Using factoring, we find:
$kQx-kx^2=(k)Qx-(k)x^2=k(Qx-x^2)=k[Q(x)-x(x)]=kx(Q-x)$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.4 - Factoring Polynomials - Exercises - Page 40: 84
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