Answer
$|4-6i|=2\sqrt {13}$
Work Step by Step
$z=5-12i$
$|a+bi|=\sqrt {a^2+b^2}$
$|4-6i|=\sqrt {4^2+(-6)^2}=\sqrt {16+36}=\sqrt {52}=\sqrt {4(13)}=2\sqrt {13}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 8 - 8.5 - The Complex Plane - 8.5 Exercises - Page 603: 19
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