Answer
The drawing of the given situation is as shown.
The area of the region is $294.52\text{ m}^2$
Work Step by Step
The drawing of the given situation is as shown.
Finding the area of the region:
$$A=\frac{\theta}{360^\circ}\pi r^2=\frac{150^\circ}{360^\circ}\pi (15)^2=294.52\text{ m}^2$$
