Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 4 - Review Exercises - Page 353: 48

Answer

$x^2= -8y$

Work Step by Step

We are told that the vertex is at the origin. $4^2=(4)(p)(-2)$ So, $p=\dfrac{16}{-8}=-2$ Since the vertex and focus have the same y-coordinate, the parabola must have a horizontal axis. Now, we will write the equation for a parabola that has a vertical axis using the vertex and $p$. $x^2=4py \implies x^2=(4)(-2) \times y $ $\implies x^2= -8y$
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