Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.7 - Probability - 11.7 Exercises - Page 837: 68

Answer

College B

Work Step by Step

Let $x$ be the population in College $A \&$ y be the population in College $B$ This means that there is an $81 \%$ chance of picking either of the 3 in $x+y$ (the total population) and is equal to the sum of percentage of the 3 in each college: $81 \%(x+y)=85 \%(x)+80 \%(y)$ $0.81(x+y)=0.85 x+0.80 y$ $0.81 x+0.81 y=0.85 x+0.80 y$ $0.01 y=0.04 x \quad \leftarrow$ Divide by $0.01 x$ $\frac{y}{x}=\frac{4}{1}$ This corresponds to the ratio of the population in College B to College A which means College B has more undergraduates.
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