Answer
$(2-i)^5=-38-41i$
Work Step by Step
$(2-i)^5=~_5C_0(2)^5+~_5C_1(2)^4(-i)^1+~_5C_2(2)^3(-i)^2+~_5C_3(2)^2(-i)^3+~_5C_4(2)^1(-i)^4+~_5C_5(-i)^5=32+5(16)(-i)+10(8)(-1)+10(4)(i)+5(2)(1)+1(-i)=-38-41i$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - 11.5 - The Binomial Theorem - 11.5 Exercises - Page 814: 68
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