Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.5 - The Binomial Theorem - 11.5 Exercises - Page 813: 56


$(2\sqrt t-1)^3=8t\sqrt t-12t+6\sqrt t-1$

Work Step by Step

$(2\sqrt t-1)^3=~_3C_0(2\sqrt t)^3(-1)^0+~_3C_1(2\sqrt t)^2(-1)^1+~_3C_2(2\sqrt t)^1(-1)^2+~_3C_3(2\sqrt t)^0(-1)^3$ $(2\sqrt t-1)^3=1(8)t\sqrt t+3(4)t(-1)+3(2)\sqrt t(1)+1(1)(-1)$ $(2\sqrt t-1)^3=8t\sqrt t-12t+6\sqrt t-1$
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