Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.1 - Sequences and Series - 11.1 Exercises - Page 779: 99


True. $\displaystyle \sum_{i=1}^{4}(i^2+2i)=\displaystyle \sum_{i=1}^{4}i^2+\displaystyle \sum_{i=1}^{4}2i$

Work Step by Step

$\displaystyle \sum_{i=1}^{4}(i^2+2i)=1^2+2(1)+2^2+2(2)+3^2+2(3)+4^2+2(4)=(1^2+2^2+3^2+4^2)+(2(1)+2(2)+2(3)+2(4))=\displaystyle \sum_{i=1}^{4}i^2+\displaystyle \sum_{i=1}^{4}2i$
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