Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter R - Test - Page R-35: 5

Answer

$\frac{12}{25}$

Work Step by Step

Simplify the fraction $\frac{48}{100}$ $\frac{48}{100}$ = $\frac{48/2}{100/2}$ = $\frac{24}{50}$ = $\frac{24/2}{50/2}$ = $\frac{12}{25}$ Result: $\frac{12}{25}$
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