Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 9 - Test - Page 675: 13

Answer

$Q=9$

Work Step by Step

$Q=kRS^2$ $Q=24; R=3; S=4$ $24=k(3)(4)^2$ $k=\frac{1}{2}$ $Q=\frac{1}{2}RS^2$ $R=2; S=3$ $Q=\frac{1}{2}(2)(3)^2$ $Q=9$
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