Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 9 - Section 9.4 - Variation and Problem Solving - Exercise Set - Page 663: 26


$1.28$ tons

Work Step by Step

Let $w$ be the maximum weight a circular column can hold. Let $h$ be the height of the circular column. $w=\frac{k}{h^2}$ $w=2; h=8$ $2=\frac{k}{8^2}$ $2=\frac{k}{64}$ $k=128$ $w=\frac{128}{h^2}$ Finding the weight a 10-foot column can hold. $w=\frac{128}{10^2}$ $w=\frac{128}{100}$ $w=1.28$ tons
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