Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 9 - Section 9.1 - Solving Systems of Linear Equations in Three Variables and Problem Solving - Practice - Page 632: 2


∅ meaning no solution

Work Step by Step

System of Equations: $2x+4y-2z=3$ $-x+y-z=6$ $x+2y-z=1$ Add equations 2 and 3 to eliminate x: $3y-2z=7$ Multiply equation 2 by 2 and add equations 1 and 2 to eliminate x: $6y-4z=15$ Solve the system of equation by multiplying equation 1 by 2 and subtracting equation 1 from equation 2: The answer you will get is $0=-8$ which is not true, therefore the system of equations has no solution. $3y-2z=7$ $6y-4z=15$
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