Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 9 - Section 9.1 - Solving Systems of Linear Equations in Three Variables and Problem Solving - Exercise Set - Page 639: 34

Answer

120 liters of 25% concentrate, 60 liters of 40% concentrate, 20 liters of 50% concentrate

Work Step by Step

25%, 40%, 50% concentrates want 200 liters of 32% $x$, $y$, $z$ are respectively the amounts of the 25%, 40%, and 50% concentrates $.25x+.4y+.5z=200*.32$ $x+y+z=200$ $x=2y$ $x+y+z=200$ $x=2y$ $2y+y+z=200$ $3y+z=200$ $.25x+.4y+.5z=200*.32$ $.25x+.4y+.5z=64$ $4*(.25x+.4y+.5z=64)$ $x+1.6y+2z=256$ $x=2y$ $x+1.6y+2z=256$ $2y+1.6y+2z=256$ $3.6y+2z=256$ $3.6y+2z-3.6y=256-3.6y$ $2z=256-3.6y$ $3y+z=200$ $2*(3y+z=200)$ $6y+2z=400$ $6y+2z-6y=400-6y$ $2z=400-6y$ $256-3.6y=400-6y$ $256-3.6y+6y-256=400-6y+6y-256$ $2.4y=144$ $2.4y/2.4=144/2.4$ $y=60$ $x=2y$ $x=2*60$ $x=120$ $x+y+z=200$ $120+60+z=200$ $180+z=200$ $180+z-180=200-180$ $z=20$
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