Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 9 - Section 9.1 - Solving Systems of Linear Equations in Three Variables and Problem Solving - Exercise Set - Page 637: 1

Answer

$(-1, 5, 2)$

Work Step by Step

A: $x-y+z=-4$ B: $3x+2y-z=5$ C: $-2x+3y-z=15$ 2A+C $2*(x-y+z)+(-2x+3y-z)=2*(-4)+15$ $2x-2y+2z-2x+3y-z=-8+15$ $2x-2x-2y+3y+2z-z=7$ $y+z=7$ 3B=C $3*(3x+2y-z=5)$ $9x+6y-3z=15$ $-2x+3y-z=15$ $9x+6y-3z=-2x+3y-z$ $11x+3y-2z=0$ -3A+B $-3*(x-y+z)+3x+2y-z=-3(-4)+5$ $-3x+3y-3z+3x+2y-z=12+5$ $5y-4z=17$ $y+z=7$ $5y-4z=17$ $4(y+z)+(5y-4z)=4*7+17$ $4y+4z+5y-4z=28+17$ $9y=45$ $9y/9=45/9$ $y=5$ $y+z=7$ $5+z=7$ $z=2$ $x-y+z=-4$ $x-5+2=-4$ $x-3=-4$ $x=-1$
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