## Algebra: A Combined Approach (4th Edition)

$y = -\frac{1}{3}x +\frac{5}{3}$
The first step is to find the slop of the line. You know it is perpendicular to $3x-y = 4$ or $3x-4 = y$. So it i perpendicular to a line with a slope of 3. To find the slope of a perpendicular line, you find the negative reciprocal of the original line. In this case, it is $-\frac{1}{3}$. Since it goes through the point $(-1,2)$, you can substitute -1 for $x$ and 2 for $y$ into the equation --> $y= -\frac{1}{3} x +b$. Then solve for b. $2= -\frac{1}{3}(-1) +b$ $2-\frac{1}{3} = b$ $\frac{5}{3} = b$ So in the linear equation --> $y=mx+b$, $m = -\frac{1}{3}$ and $b=\frac{5}{3}$. The answer is thus: $y = -\frac{1}{3}x +\frac{5}{3}$