Answer
Please see the graph.
Work Step by Step
Green line: $f(x)=x^2$
Red line: $g(x)=(x+2)^2-1$
We pick three values of $x$ to determine the applicable values of the function (and to determine the $y$ value for graphing).
We pick $x=-2$, $x=0$, and $x=1$.
$x=-2$
Green line: $f(x)=x^2$
$f(x)=x^2$
$f(-2)=(-2)^2$
$f(-2)=4$
$x=0$
Green line: $f(x)=x^2$
$f(x)=x^2$
$f(0)=0^2$
$f(0)=0$
$x=1$
Green line: $f(x)=x^2$
$f(x)=x^2$
$f(1)=1^2$
$f(1)=1$
The points $(-2,4)$, $(0,0)$, and $(1,1)$ are on the graph of the green line.
$x=-2$
Red line: $g(x)=(x+2)^2-1$
$g(x)=(x+2)^2-1$
$g(-2)=(-2+2)^2-1$
$g(-2)=0^2-1$
$g(-2)=0-1$
$g(-2)=-1$
$x=0$
Red line: $g(x)=(x+2)^2-1$
$g(x)=(x+2)^2-1$
$g(0)=(0+2)^2-1$
$g(0)=2^2-1$
$g(0)=4-1$
$g(0)=3$
$x=1$
Red line: $g(x)=(x+2)^2-1$
$g(x)=(x+2)^2-1$
$g(1)=(1+2)^2-1$
$g(1)=3^2-1$
$g(1)=9-1$
$g(1)=8$
The points $(-2,-1)$, $(0,3)$, and $(1,8)$ are on the graph of the red line.
