#### Answer

$-x^2-6x+10$

#### Work Step by Step

If $Q(x) = 4x^2-6x+3$ and $R(x) = 5x^2-7$
$Q(x) - R(x) = 4x^2-6x+3 - (5x^2-7) = 4x^2-6x+3-5x^2+7 = -x^2-6x+10$

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$-x^2-6x+10$

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