Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 8 - Section 8.3 - Polynomial and Rational Functions - Exercise Set - Page 595: 43


The solution is 2

Work Step by Step

$\frac{x-3}{2}$=$\frac{x-5}{6}$ 2(x-5)=6(x-3) 2x-10=6x-18 2x-6x=-18+10 -4x=-8 x=2 The solution is 2 Check Let x=2 $\frac{x-3}{2}$=$\frac{x-5}{6}$ $\frac{2-3}{2}$=$\frac{2-5}{6}$ $\frac{-1}{2}$=$\frac{x-3}{6}$ $\frac{-1}{2}$=$\frac{-1}{2}$
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