Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 8 - Section 8.2 - Introduction to Functions - Practice: 8

Answer

Not a function

Work Step by Step

The problem is to determine if $x$ = $y^{2}$ + 1 is a function. We can determine this by solving the problem; for example, let $x$ = 5 and $y$ = 2. 5 = $2^{2}$ + 1 and 5 = $(-2)^{2}$ + 1 Both 2 and -2 could be the value for $y$, therefore it is not a function.
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