Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 8 - Review - Page 619: 6



Work Step by Step

through (-6,-1) and perpendicular to 4x+3y=5 4x+3y=5 3y=5-4x y=$\frac{5-4x}{3}$ y=$\frac{-4x}{3}$+$\frac{5}{3}$ slope $\frac{-4}{3}$ the line perpendicular to this line ,has the slope $\frac{3}{4}$ our line has slope $\frac{3}{4}$ through (-6,-1) -1=$\frac{3}{4}$(-6)+b -$\frac{2}{2}$=-$\frac{9}{2}$+b -$\frac{2}{2}$+$\frac{9}{2}$=b $\frac{7}{2}$=b y=mx+b y=$\frac{3}{4}$x+$\frac{7}{2}$
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